25(x-4)=5(2x+8)+25(4-x)

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Solution for 25(x-4)=5(2x+8)+25(4-x) equation: 



25(x-4)=5(2x+8)+25(4-x)

We move all terms to the left:

25(x-4)-(5(2x+8)+25(4-x))=0

We add all the numbers together, and all the variables

25(x-4)-(5(2x+8)+25(-1x+4))=0

We multiply parentheses

25x-(5(2x+8)+25(-1x+4))-100=0



We calculate terms in parentheses: -(5(2x+8)+25(-1x+4)), so:

5(2x+8)+25(-1x+4)

We multiply parentheses

10x-25x+40+100

We add all the numbers together, and all the variables

-15x+140

Back to the equation:

-(-15x+140)



We get rid of parentheses

25x+15x-140-100=0

We add all the numbers together, and all the variables

40x-240=0

We move all terms containing x to the left, all other terms to the right

40x=240

x=240/40

x=6

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