25(y+2)=5(4y+5)=

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Solution for 25(y+2)=5(4y+5)= equation: 



25(y+2)=5(4y+5)=

We move all terms to the left:

25(y+2)-(5(4y+5))=0

We multiply parentheses

25y-(5(4y+5))+50=0



We calculate terms in parentheses: -(5(4y+5)), so:

5(4y+5)

We multiply parentheses

20y+25

Back to the equation:

-(20y+25)



We get rid of parentheses

25y-20y-25+50=0

We add all the numbers together, and all the variables

5y+25=0

We move all terms containing y to the left, all other terms to the right

5y=-25

y=-25/5

y=-5

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