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25+(10-5x)=10-(2-15x)
We move all terms to the left:
25+(10-5x)-(10-(2-15x))=0
We add all the numbers together, and all the variables
(-5x+10)-(10-(-15x+2))+25=0
We get rid of parentheses
-5x-(10-(-15x+2))+10+25=0
We calculate terms in parentheses: -(10-(-15x+2)), so:We add all the numbers together, and all the variables
10-(-15x+2)
determiningTheFunctionDomain -(-15x+2)+10
We get rid of parentheses
15x-2+10
We add all the numbers together, and all the variables
15x+8
Back to the equation:
-(15x+8)
-5x-(15x+8)+35=0
We get rid of parentheses
-5x-15x-8+35=0
We add all the numbers together, and all the variables
-20x+27=0
We move all terms containing x to the left, all other terms to the right
-20x=-27
x=-27/-20
x=1+7/20
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