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25+-130x+120x^2=0
We add all the numbers together, and all the variables
120x^2-130x=0
a = 120; b = -130; c = 0;
Δ = b2-4ac
Δ = -1302-4·120·0
Δ = 16900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16900}=130$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-130)-130}{2*120}=\frac{0}{240} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-130)+130}{2*120}=\frac{260}{240} =1+1/12 $
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