25+3(2x-5)-9x=-5-3(-5+2x)+3x

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Solution for 25+3(2x-5)-9x=-5-3(-5+2x)+3x equation: 



25+3(2x-5)-9x=-5-3(-5+2x)+3x

We move all terms to the left:

25+3(2x-5)-9x-(-5-3(-5+2x)+3x)=0

We add all the numbers together, and all the variables

3(2x-5)-9x-(-5-3(2x-5)+3x)+25=0

We add all the numbers together, and all the variables

-9x+3(2x-5)-(-5-3(2x-5)+3x)+25=0

We multiply parentheses

-9x+6x-(-5-3(2x-5)+3x)-15+25=0



We calculate terms in parentheses: -(-5-3(2x-5)+3x), so:

-5-3(2x-5)+3x

determiningTheFunctionDomain
-3(2x-5)+3x-5

We add all the numbers together, and all the variables

3x-3(2x-5)-5

We multiply parentheses

3x-6x+15-5

We add all the numbers together, and all the variables

-3x+10

Back to the equation:

-(-3x+10)



We add all the numbers together, and all the variables

-3x-(-3x+10)+10=0

We get rid of parentheses

-3x+3x-10+10=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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