25+3y-2=12y-12-4y

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Solution for 25+3y-2=12y-12-4y equation: 



25+3y-2=12y-12-4y

We move all terms to the left:

25+3y-2-(12y-12-4y)=0

We add all the numbers together, and all the variables

3y-(8y-12)+25-2=0

We add all the numbers together, and all the variables

3y-(8y-12)+23=0

We get rid of parentheses

3y-8y+12+23=0

We add all the numbers together, and all the variables

-5y+35=0

We move all terms containing y to the left, all other terms to the right

-5y=-35

y=-35/-5

y=+7

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