25+5(y+20)=3(y-1)

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Solution for 25+5(y+20)=3(y-1) equation:


Simplifying
25 + 5(y + 20) = 3(y + -1)

Reorder the terms:
25 + 5(20 + y) = 3(y + -1)
25 + (20 * 5 + y * 5) = 3(y + -1)
25 + (100 + 5y) = 3(y + -1)

Combine like terms: 25 + 100 = 125
125 + 5y = 3(y + -1)

Reorder the terms:
125 + 5y = 3(-1 + y)
125 + 5y = (-1 * 3 + y * 3)
125 + 5y = (-3 + 3y)

Solving
125 + 5y = -3 + 3y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-3y' to each side of the equation.
125 + 5y + -3y = -3 + 3y + -3y

Combine like terms: 5y + -3y = 2y
125 + 2y = -3 + 3y + -3y

Combine like terms: 3y + -3y = 0
125 + 2y = -3 + 0
125 + 2y = -3

Add '-125' to each side of the equation.
125 + -125 + 2y = -3 + -125

Combine like terms: 125 + -125 = 0
0 + 2y = -3 + -125
2y = -3 + -125

Combine like terms: -3 + -125 = -128
2y = -128

Divide each side by '2'.
y = -64

Simplifying
y = -64

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