25-(17-2x)=2x(8x-6)

Solution for 25-(17-2x)=2x(8x-6) equation:

25-(17-2x)=2x(8x-6)

We move all terms to the left:

25-(17-2x)-(2x(8x-6))=0

We add all the numbers together, and all the variables

-(-2x+17)-(2x(8x-6))+25=0

We get rid of parentheses

2x-(2x(8x-6))-17+25=0


We calculate terms in parentheses: -(2x(8x-6)), so:

2x(8x-6)

We multiply parentheses

16x^2-12x

Back to the equation:

-(16x^2-12x)


We add all the numbers together, and all the variables

2x-(16x^2-12x)+8=0

We get rid of parentheses

-16x^2+2x+12x+8=0

We add all the numbers together, and all the variables

-16x^2+14x+8=0

a = -16; b = 14; c = +8;
Δ = b2-4ac
Δ = 142-4·(-16)·8
Δ = 708
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{708}=\sqrt{4*177}=\sqrt{4}*\sqrt{177}=2\sqrt{177}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2\sqrt{177}}{2*-16}=\frac{-14-2\sqrt{177}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2\sqrt{177}}{2*-16}=\frac{-14+2\sqrt{177}}{-32}
$