25-(2c+3)=2(c+6)=c

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Solution for 25-(2c+3)=2(c+6)=c equation: 



25-(2c+3)=2(c+6)=c

We move all terms to the left:

25-(2c+3)-(2(c+6))=0

We get rid of parentheses

-2c-(2(c+6))-3+25=0



We calculate terms in parentheses: -(2(c+6)), so:

2(c+6)

We multiply parentheses

2c+12

Back to the equation:

-(2c+12)



We add all the numbers together, and all the variables

-2c-(2c+12)+22=0

We get rid of parentheses

-2c-2c-12+22=0

We add all the numbers together, and all the variables

-4c+10=0

We move all terms containing c to the left, all other terms to the right

-4c=-10

c=-10/-4

c=2+1/2

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