25-(3x+)=2(x+8)x+

Solution for 25-(3x+)=2(x+8)x+ equation:

25-(3x+)=2(x+8)x+

We move all terms to the left:

25-(3x+)-(2(x+8)x+)=0

We add all the numbers together, and all the variables

-(+3x)-(2(x+8)x+)+25=0

We get rid of parentheses

-3x-(2(x+8)x+)+25=0


We calculate terms in parentheses: -(2(x+8)x+), so:

2(x+8)x+

We add all the numbers together, and all the variables

2(x+8)x

We multiply parentheses

2x^2+16x

Back to the equation:

-(2x^2+16x)


We get rid of parentheses

-2x^2-3x-16x+25=0

We add all the numbers together, and all the variables

-2x^2-19x+25=0

a = -2; b = -19; c = +25;
Δ = b2-4ac
Δ = -192-4·(-2)·25
Δ = 561
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-\sqrt{561}}{2*-2}=\frac{19-\sqrt{561}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+\sqrt{561}}{2*-2}=\frac{19+\sqrt{561}}{-4}
$