25-(4+5y-2(y+4))=-5(2y-3)-(5(y-1)-10y+1)

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Solution for 25-(4+5y-2(y+4))=-5(2y-3)-(5(y-1)-10y+1) equation:



25-(4+5y-2(y+4))=-5(2y-3)-(5(y-1)-10y+1)
We move all terms to the left:
25-(4+5y-2(y+4))-(-5(2y-3)-(5(y-1)-10y+1))=0
We calculate terms in parentheses: -(4+5y-2(y+4)), so:
4+5y-2(y+4)
determiningTheFunctionDomain 5y-2(y+4)+4
We multiply parentheses
5y-2y-8+4
We add all the numbers together, and all the variables
3y-4
Back to the equation:
-(3y-4)
We calculate terms in parentheses: -(-5(2y-3)-(5(y-1)-10y+1)), so:
-5(2y-3)-(5(y-1)-10y+1)
We multiply parentheses
-10y-(5(y-1)-10y+1)+15
We calculate terms in parentheses: -(5(y-1)-10y+1), so:
5(y-1)-10y+1
We add all the numbers together, and all the variables
-10y+5(y-1)+1
We multiply parentheses
-10y+5y-5+1
We add all the numbers together, and all the variables
-5y-4
Back to the equation:
-(-5y-4)
We get rid of parentheses
-10y+5y+4+15
We add all the numbers together, and all the variables
-5y+19
Back to the equation:
-(-5y+19)
We get rid of parentheses
-3y+5y+4-19+25=0
We add all the numbers together, and all the variables
2y+10=0
We move all terms containing y to the left, all other terms to the right
2y=-10
y=-10/2
y=-5

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