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25-(5x+10)=6x-(x+2)+(2x-5)
We move all terms to the left:
25-(5x+10)-(6x-(x+2)+(2x-5))=0
We get rid of parentheses
-5x-(6x-(x+2)+(2x-5))-10+25=0
We calculate terms in parentheses: -(6x-(x+2)+(2x-5)), so:We add all the numbers together, and all the variables
6x-(x+2)+(2x-5)
We get rid of parentheses
6x-x+2x-2-5
We add all the numbers together, and all the variables
7x-7
Back to the equation:
-(7x-7)
-5x-(7x-7)+15=0
We get rid of parentheses
-5x-7x+7+15=0
We add all the numbers together, and all the variables
-12x+22=0
We move all terms containing x to the left, all other terms to the right
-12x=-22
x=-22/-12
x=1+5/6
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