25-(c+3)=2(c+6)+c

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Solution for 25-(c+3)=2(c+6)+c equation: 



25-(c+3)=2(c+6)+c

We move all terms to the left:

25-(c+3)-(2(c+6)+c)=0

We get rid of parentheses

-c-(2(c+6)+c)-3+25=0



We calculate terms in parentheses: -(2(c+6)+c), so:

2(c+6)+c

We add all the numbers together, and all the variables

c+2(c+6)

We multiply parentheses

c+2c+12

We add all the numbers together, and all the variables

3c+12

Back to the equation:

-(3c+12)



We add all the numbers together, and all the variables

-1c-(3c+12)+22=0

We get rid of parentheses

-1c-3c-12+22=0

We add all the numbers together, and all the variables

-4c+10=0

We move all terms containing c to the left, all other terms to the right

-4c=-10

c=-10/-4

c=2+1/2

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