25-2(3y-4)=7y+1

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Solution for 25-2(3y-4)=7y+1 equation: 



25-2(3y-4)=7y+1

We move all terms to the left:

25-2(3y-4)-(7y+1)=0

We multiply parentheses

-6y-(7y+1)+8+25=0

We get rid of parentheses

-6y-7y-1+8+25=0

We add all the numbers together, and all the variables

-13y+32=0

We move all terms containing y to the left, all other terms to the right

-13y=-32

y=-32/-13

y=2+6/13

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