25-2z=3(z-5)

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Solution for 25-2z=3(z-5) equation: 



25-2z=3(z-5)

We move all terms to the left:

25-2z-(3(z-5))=0



We calculate terms in parentheses: -(3(z-5)), so:

3(z-5)

We multiply parentheses

3z-15

Back to the equation:

-(3z-15)



We get rid of parentheses

-2z-3z+15+25=0

We add all the numbers together, and all the variables

-5z+40=0

We move all terms containing z to the left, all other terms to the right

-5z=-40

z=-40/-5

z=+8

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