25-3(x+5)=6+6(2-x)

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Solution for 25-3(x+5)=6+6(2-x) equation: 



25-3(x+5)=6+6(2-x)

We move all terms to the left:

25-3(x+5)-(6+6(2-x))=0

We add all the numbers together, and all the variables

-3(x+5)-(6+6(-1x+2))+25=0

We multiply parentheses

-3x-(6+6(-1x+2))-15+25=0



We calculate terms in parentheses: -(6+6(-1x+2)), so:

6+6(-1x+2)

determiningTheFunctionDomain
6(-1x+2)+6

We multiply parentheses

-6x+12+6

We add all the numbers together, and all the variables

-6x+18

Back to the equation:

-(-6x+18)



We add all the numbers together, and all the variables

-3x-(-6x+18)+10=0

We get rid of parentheses

-3x+6x-18+10=0

We add all the numbers together, and all the variables

3x-8=0

We move all terms containing x to the left, all other terms to the right

3x=8

x=8/3

x=2+2/3

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