25-4(2x-3)=16+(5x-4)

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Solution for 25-4(2x-3)=16+(5x-4) equation: 



25-4(2x-3)=16+(5x-4)

We move all terms to the left:

25-4(2x-3)-(16+(5x-4))=0

We multiply parentheses

-8x-(16+(5x-4))+12+25=0



We calculate terms in parentheses: -(16+(5x-4)), so:

16+(5x-4)

determiningTheFunctionDomain
(5x-4)+16

We get rid of parentheses

5x-4+16

We add all the numbers together, and all the variables

5x+12

Back to the equation:

-(5x+12)



We add all the numbers together, and all the variables

-8x-(5x+12)+37=0

We get rid of parentheses

-8x-5x-12+37=0

We add all the numbers together, and all the variables

-13x+25=0

We move all terms containing x to the left, all other terms to the right

-13x=-25

x=-25/-13

x=1+12/13

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