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25-4(2x-3)=16+(5x-4)/2
We move all terms to the left:
25-4(2x-3)-(16+(5x-4)/2)=0
We multiply parentheses
-8x-(16+(5x-4)/2)+12+25=0
We multiply all the terms by the denominator
-8x*2)-(16+(5x-4)+12*2)+25*2)=0
We add all the numbers together, and all the variables
-8x*2)-(16+(5x-4)=0
Wy multiply elements
-16x^2+(5x-4)=0
We get rid of parentheses
-16x^2+5x-4=0
a = -16; b = 5; c = -4;
Δ = b2-4ac
Δ = 52-4·(-16)·(-4)
Δ = -231
Delta is less than zero, so there is no solution for the equation
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