25-4(2x-3)=16+(5x-4)2

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Solution for 25-4(2x-3)=16+(5x-4)2 equation: 



25-4(2x-3)=16+(5x-4)2

We move all terms to the left:

25-4(2x-3)-(16+(5x-4)2)=0

We multiply parentheses

-8x-(16+(5x-4)2)+12+25=0



We calculate terms in parentheses: -(16+(5x-4)2), so:

16+(5x-4)2

determiningTheFunctionDomain
(5x-4)2+16

We multiply parentheses

10x-8+16

We add all the numbers together, and all the variables

10x+8

Back to the equation:

-(10x+8)



We add all the numbers together, and all the variables

-8x-(10x+8)+37=0

We get rid of parentheses

-8x-10x-8+37=0

We add all the numbers together, and all the variables

-18x+29=0

We move all terms containing x to the left, all other terms to the right

-18x=-29

x=-29/-18

x=1+11/18

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