25-4(2x-3)=16+(5x-4)x2

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Solution for 25-4(2x-3)=16+(5x-4)x2 equation:



25-4(2x-3)=16+(5x-4)x2
We move all terms to the left:
25-4(2x-3)-(16+(5x-4)x2)=0
We multiply parentheses
-8x-(16+(5x-4)x2)+12+25=0
We calculate terms in parentheses: -(16+(5x-4)x2), so:
16+(5x-4)x2
determiningTheFunctionDomain (5x-4)x2+16
We multiply parentheses
5x^3-4x^2+16
We do not support expression: x^3

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