25-4(3x-5)=7(4x-3)

Solution for 25-4(3x-5)=7(4x-3) equation:

25-4(3x-5)=7(4x-3)

We move all terms to the left:

25-4(3x-5)-(7(4x-3))=0

We multiply parentheses

-12x-(7(4x-3))+20+25=0


We calculate terms in parentheses: -(7(4x-3)), so:

7(4x-3)

We multiply parentheses

28x-21

Back to the equation:

-(28x-21)


We add all the numbers together, and all the variables

-12x-(28x-21)+45=0

We get rid of parentheses

-12x-28x+21+45=0

We add all the numbers together, and all the variables

-40x+66=0

We move all terms containing x to the left, all other terms to the right

-40x=-66

x=-66/-40

x=1+13/20