25-r2=4r-5r2+10

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Solution for 25-r2=4r-5r2+10 equation: 



25-r2=4r-5r^2+10

We move all terms to the left:

25-r2-(4r-5r^2+10)=0

We add all the numbers together, and all the variables

-1r^2-(4r-5r^2+10)+25=0

We get rid of parentheses

-1r^2+5r^2-4r-10+25=0

We add all the numbers together, and all the variables

4r^2-4r+15=0

a = 4; b = -4; c = +15;
Δ = b2-4ac
Δ = -42-4·4·15
Δ = -224
Delta is less than zero, so there is no solution for the equation

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