25/(p-16)=9/p

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Solution for 25/(p-16)=9/p equation: 



25/(p-16)=9/p

We move all terms to the left:

25/(p-16)-(9/p)=0



Domain of the equation: (p-16)!=0

We move all terms containing p to the left, all other terms to the right

p!=16

p∈R





Domain of the equation: p)!=0

p!=0/1

p!=0

p∈R



We add all the numbers together, and all the variables

25/(p-16)-(+9/p)=0

We get rid of parentheses

25/(p-16)-9/p=0

We calculate fractions


25p/(p^2-16p)+(-9p+144)/(p^2-16p)=0

We multiply all the terms by the denominator


25p+(-9p+144)=0

We get rid of parentheses

25p-9p+144=0

We add all the numbers together, and all the variables

16p+144=0

We move all terms containing p to the left, all other terms to the right

16p=-144

p=-144/16

p=-9

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