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25/2y+4=5/2
We move all terms to the left:
25/2y+4-(5/2)=0
Domain of the equation: 2y!=0We add all the numbers together, and all the variables
y!=0/2
y!=0
y∈R
25/2y+4-(+5/2)=0
We get rid of parentheses
25/2y+4-5/2=0
We calculate fractions
4!=0
There is no solution for this equation
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