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25/6m-5/3m=7
We move all terms to the left:
25/6m-5/3m-(7)=0
Domain of the equation: 6m!=0
m!=0/6
m!=0
m∈R
Domain of the equation: 3m!=0We calculate fractions
m!=0/3
m!=0
m∈R
75m/18m^2+(-30m)/18m^2-7=0
We multiply all the terms by the denominator
75m+(-30m)-7*18m^2=0
Wy multiply elements
-126m^2+75m+(-30m)=0
We get rid of parentheses
-126m^2+75m-30m=0
We add all the numbers together, and all the variables
-126m^2+45m=0
a = -126; b = 45; c = 0;
Δ = b2-4ac
Δ = 452-4·(-126)·0
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2025}=45$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-45}{2*-126}=\frac{-90}{-252} =5/14 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+45}{2*-126}=\frac{0}{-252} =0 $
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