25/6p+1=1+6p

Solution for 25/6p+1=1+6p equation:

25/6p+1=1+6p

We move all terms to the left:

25/6p+1-(1+6p)=0


Domain of the equation: 6p!=0

p!=0/6

p!=0

p∈R


We add all the numbers together, and all the variables

25/6p-(6p+1)+1=0

We get rid of parentheses

25/6p-6p-1+1=0

We multiply all the terms by the denominator


-6p*6p-1*6p+1*6p+25=0

Wy multiply elements

-36p^2-6p+6p+25=0

We add all the numbers together, and all the variables

-36p^2+25=0

a = -36; b = 0; c = +25;
Δ = b2-4ac
Δ = 02-4·(-36)·25
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60}{2*-36}=\frac{-60}{-72}
=5/6
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60}{2*-36}=\frac{60}{-72}
=-5/6
$