25/m+3=m+3

Solution for 25/m+3=m+3 equation:

25/m+3=m+3

We move all terms to the left:

25/m+3-(m+3)=0


Domain of the equation: m!=0

m∈R


We get rid of parentheses

25/m-m-3+3=0

We multiply all the terms by the denominator


-m*m-3*m+3*m+25=0

We add all the numbers together, and all the variables

-m*m+25=0

Wy multiply elements

-1m^2+25=0

a = -1; b = 0; c = +25;
Δ = b2-4ac
Δ = 02-4·(-1)·25
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10}{2*-1}=\frac{-10}{-2}
=+5
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10}{2*-1}=\frac{10}{-2}
=-5
$