250(x+5)(2x-1)=0

Solution for 250(x+5)(2x-1)=0 equation:

250(x+5)(2x-1)=0

We multiply parentheses ..

250(+2x^2-1x+10x-5)=0

We multiply parentheses

500x^2-250x+2500x-1250=0

We add all the numbers together, and all the variables

500x^2+2250x-1250=0

a = 500; b = 2250; c = -1250;
Δ = b2-4ac
Δ = 22502-4·500·(-1250)
Δ = 7562500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7562500}=2750$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2250)-2750}{2*500}=\frac{-5000}{1000}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2250)+2750}{2*500}=\frac{500}{1000}
=1/2
$