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250=x(0.5x-5)
We move all terms to the left:
250-(x(0.5x-5))=0
We calculate terms in parentheses: -(x(0.5x-5)), so:We get rid of parentheses
x(0.5x-5)
We multiply parentheses
0x^2-5x
We add all the numbers together, and all the variables
x^2-5x
Back to the equation:
-(x^2-5x)
-x^2+5x+250=0
We add all the numbers together, and all the variables
-1x^2+5x+250=0
a = -1; b = 5; c = +250;
Δ = b2-4ac
Δ = 52-4·(-1)·250
Δ = 1025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1025}=\sqrt{25*41}=\sqrt{25}*\sqrt{41}=5\sqrt{41}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5\sqrt{41}}{2*-1}=\frac{-5-5\sqrt{41}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5\sqrt{41}}{2*-1}=\frac{-5+5\sqrt{41}}{-2} $
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