255=r2

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Solution for 255=r2 equation:



255=r2
We move all terms to the left:
255-(r2)=0
We add all the numbers together, and all the variables
-1r^2+255=0
a = -1; b = 0; c = +255;
Δ = b2-4ac
Δ = 02-4·(-1)·255
Δ = 1020
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{1020}=\sqrt{4*255}=\sqrt{4}*\sqrt{255}=2\sqrt{255}$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{255}}{2*-1}=\frac{0-2\sqrt{255}}{-2} =-\frac{2\sqrt{255}}{-2} =-\frac{\sqrt{255}}{-1} $
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{255}}{2*-1}=\frac{0+2\sqrt{255}}{-2} =\frac{2\sqrt{255}}{-2} =\frac{\sqrt{255}}{-1} $

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