256y2-32y+1=0

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Solution for 256y2-32y+1=0 equation: 



256y^2-32y+1=0

a = 256; b = -32; c = +1;
Δ = b2-4ac
Δ = -322-4·256·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{32}{512}=1/16$

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