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258-3/8m=5m
We move all terms to the left:
258-3/8m-(5m)=0
Domain of the equation: 8m!=0We add all the numbers together, and all the variables
m!=0/8
m!=0
m∈R
-5m-3/8m+258=0
We multiply all the terms by the denominator
-5m*8m+258*8m-3=0
Wy multiply elements
-40m^2+2064m-3=0
a = -40; b = 2064; c = -3;
Δ = b2-4ac
Δ = 20642-4·(-40)·(-3)
Δ = 4259616
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4259616}=\sqrt{16*266226}=\sqrt{16}*\sqrt{266226}=4\sqrt{266226}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2064)-4\sqrt{266226}}{2*-40}=\frac{-2064-4\sqrt{266226}}{-80} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2064)+4\sqrt{266226}}{2*-40}=\frac{-2064+4\sqrt{266226}}{-80} $
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