25=(1/4)n-3

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Solution for 25=(1/4)n-3 equation: 



25=(1/4)n-3

We move all terms to the left:

25-((1/4)n-3)=0



Domain of the equation: 4)n-3)!=0

n!=0/1

n!=0

n∈R



We add all the numbers together, and all the variables

-((+1/4)n-3)+25=0

We multiply all the terms by the denominator


-((+1+25*4)n-3)=0



We calculate terms in parentheses: -((+1+25*4)n-3), so:

(+1+25*4)n-3

We add all the numbers together, and all the variables

101n-3

Back to the equation:

-(101n-3)



We get rid of parentheses

-101n+3=0

We move all terms containing n to the left, all other terms to the right

-101n=-3

n=-3/-101

n=3/101

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