25=-16t2+25

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Solution for 25=-16t2+25 equation: 



25=-16t^2+25

We move all terms to the left:

25-(-16t^2+25)=0

We get rid of parentheses

16t^2-25+25=0

We add all the numbers together, and all the variables

16t^2=0

a = 16; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·16·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{0}{32}=0$

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