25=-3(22-y)+2(y-2)

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Solution for 25=-3(22-y)+2(y-2) equation: 



25=-3(22-y)+2(y-2)

We move all terms to the left:

25-(-3(22-y)+2(y-2))=0

We add all the numbers together, and all the variables

-(-3(-1y+22)+2(y-2))+25=0



We calculate terms in parentheses: -(-3(-1y+22)+2(y-2)), so:

-3(-1y+22)+2(y-2)

We multiply parentheses

3y+2y-66-4

We add all the numbers together, and all the variables

5y-70

Back to the equation:

-(5y-70)



We get rid of parentheses

-5y+70+25=0

We add all the numbers together, and all the variables

-5y+95=0

We move all terms containing y to the left, all other terms to the right

-5y=-95

y=-95/-5

y=+19

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