25=-3(22-y)+2y-2

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Solution for 25=-3(22-y)+2y-2 equation: 



25=-3(22-y)+2y-2

We move all terms to the left:

25-(-3(22-y)+2y-2)=0

We add all the numbers together, and all the variables

-(-3(-1y+22)+2y-2)+25=0



We calculate terms in parentheses: -(-3(-1y+22)+2y-2), so:

-3(-1y+22)+2y-2

We add all the numbers together, and all the variables

2y-3(-1y+22)-2

We multiply parentheses

2y+3y-66-2

We add all the numbers together, and all the variables

5y-68

Back to the equation:

-(5y-68)



We get rid of parentheses

-5y+68+25=0

We add all the numbers together, and all the variables

-5y+93=0

We move all terms containing y to the left, all other terms to the right

-5y=-93

y=-93/-5

y=18+3/5

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