25=-3(c+2)+2c

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Solution for 25=-3(c+2)+2c equation: 



25=-3(c+2)+2c

We move all terms to the left:

25-(-3(c+2)+2c)=0



We calculate terms in parentheses: -(-3(c+2)+2c), so:

-3(c+2)+2c

We add all the numbers together, and all the variables

2c-3(c+2)

We multiply parentheses

2c-3c-6

We add all the numbers together, and all the variables

-1c-6

Back to the equation:

-(-1c-6)



We get rid of parentheses

1c+6+25=0

We add all the numbers together, and all the variables

c+31=0

We move all terms containing c to the left, all other terms to the right

c=-31

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