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25=1/2(10x+2)+3x
We move all terms to the left:
25-(1/2(10x+2)+3x)=0
Domain of the equation: 2(10x+2)+3x)!=0We multiply all the terms by the denominator
x∈R
-(1+25*2(10x+2)+3x)=0
We calculate terms in parentheses: -(1+25*2(10x+2)+3x), so:We add all the numbers together, and all the variables
1+25*2(10x+2)+3x
determiningTheFunctionDomain 25*2(10x+2)+3x+1
We add all the numbers together, and all the variables
3x+25*2(10x+2)+1
Wy multiply elements
3x+50x(1+1
Back to the equation:
-(3x+50x(1+1)
-(3x+50x2=0
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