25=1/5b+35

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Solution for 25=1/5b+35 equation: 



25=1/5b+35

We move all terms to the left:

25-(1/5b+35)=0



Domain of the equation: 5b+35)!=0

b∈R



We get rid of parentheses

-1/5b-35+25=0

We multiply all the terms by the denominator


-35*5b+25*5b-1=0

Wy multiply elements

-175b+125b-1=0

We add all the numbers together, and all the variables

-50b-1=0

We move all terms containing b to the left, all other terms to the right

-50b=1

b=1/-50

b=-1/50

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