25=1/5x+35

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Solution for 25=1/5x+35 equation: 



25=1/5x+35

We move all terms to the left:

25-(1/5x+35)=0



Domain of the equation: 5x+35)!=0

x∈R



We get rid of parentheses

-1/5x-35+25=0

We multiply all the terms by the denominator


-35*5x+25*5x-1=0

Wy multiply elements

-175x+125x-1=0

We add all the numbers together, and all the variables

-50x-1=0

We move all terms containing x to the left, all other terms to the right

-50x=1

x=1/-50

x=-1/50

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