25=2(1/4n+1)+2n

Solution for 25=2(1/4n+1)+2n equation:

25=2(1/4n+1)+2n

We move all terms to the left:

25-(2(1/4n+1)+2n)=0


Domain of the equation: 4n+1)+2n)!=0

n∈R


We multiply all the terms by the denominator


-(2(1+25*4n+1)+2n)=0


We calculate terms in parentheses: -(2(1+25*4n+1)+2n), so:

2(1+25*4n+1)+2n

We add all the numbers together, and all the variables

2(25*4n+2)+2n

We add all the numbers together, and all the variables

2n+2(25*4n+2)

We multiply parentheses

2n+200n+4

We add all the numbers together, and all the variables

202n+4

Back to the equation:

-(202n+4)


We get rid of parentheses

-202n-4=0

We move all terms containing n to the left, all other terms to the right

-202n=4

n=4/-202

n=-2/101