25=2/5f

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Solution for 25=2/5f equation: 



25=2/5f

We move all terms to the left:

25-(2/5f)=0



Domain of the equation: 5f)!=0

f!=0/1

f!=0

f∈R



We add all the numbers together, and all the variables

-(+2/5f)+25=0

We get rid of parentheses

-2/5f+25=0

We multiply all the terms by the denominator


25*5f-2=0

Wy multiply elements

125f-2=0

We move all terms containing f to the left, all other terms to the right

125f=2

f=2/125

f=2/125

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