25=3(2x+2)+5(2x+1)

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Solution for 25=3(2x+2)+5(2x+1) equation: 



25=3(2x+2)+5(2x+1)

We move all terms to the left:

25-(3(2x+2)+5(2x+1))=0



We calculate terms in parentheses: -(3(2x+2)+5(2x+1)), so:

3(2x+2)+5(2x+1)

We multiply parentheses

6x+10x+6+5

We add all the numbers together, and all the variables

16x+11

Back to the equation:

-(16x+11)



We get rid of parentheses

-16x-11+25=0

We add all the numbers together, and all the variables

-16x+14=0

We move all terms containing x to the left, all other terms to the right

-16x=-14

x=-14/-16

x=7/8

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