25=3+(t+2)-2t

Solution for 25=3+(t+2)-2t equation:

25=3+(t+2)-2t

We move all terms to the left:

25-(3+(t+2)-2t)=0


We calculate terms in parentheses: -(3+(t+2)-2t), so:

3+(t+2)-2t

determiningTheFunctionDomain
(t+2)-2t+3

We add all the numbers together, and all the variables

-2t+(t+2)+3

We get rid of parentheses

-2t+t+2+3

We add all the numbers together, and all the variables

-1t+5

Back to the equation:

-(-1t+5)


We get rid of parentheses

1t-5+25=0

We add all the numbers together, and all the variables

t+20=0

We move all terms containing t to the left, all other terms to the right

t=-20