25=5(2-n)-2(-3+2n)

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Solution for 25=5(2-n)-2(-3+2n) equation: 



25=5(2-n)-2(-3+2n)

We move all terms to the left:

25-(5(2-n)-2(-3+2n))=0

We add all the numbers together, and all the variables

-(5(-1n+2)-2(2n-3))+25=0



We calculate terms in parentheses: -(5(-1n+2)-2(2n-3)), so:

5(-1n+2)-2(2n-3)

We multiply parentheses

-5n-4n+10+6

We add all the numbers together, and all the variables

-9n+16

Back to the equation:

-(-9n+16)



We get rid of parentheses

9n-16+25=0

We add all the numbers together, and all the variables

9n+9=0

We move all terms containing n to the left, all other terms to the right

9n=-9

n=-9/9

n=-1

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