25=5+(t/2-2)

Solution for 25=5+(t/2-2) equation:

25=5+(t/2-2)

We move all terms to the left:

25-(5+(t/2-2))=0

We multiply all the terms by the denominator


-(5+(t+25*2-2))=0


We calculate terms in parentheses: -(5+(t+25*2-2)), so:

5+(t+25*2-2)

determiningTheFunctionDomain
(t+25*2-2)+5

We add all the numbers together, and all the variables

(t+48)+5

We get rid of parentheses

t+48+5

We add all the numbers together, and all the variables

t+53

Back to the equation:

-(t+53)


We get rid of parentheses

-t-53=0

We add all the numbers together, and all the variables

-1t-53=0

We move all terms containing t to the left, all other terms to the right

-t=53

t=53/-1

t=-53