25=9/5f+32

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Solution for 25=9/5f+32 equation: 



25=9/5f+32

We move all terms to the left:

25-(9/5f+32)=0



Domain of the equation: 5f+32)!=0

f∈R



We get rid of parentheses

-9/5f-32+25=0

We multiply all the terms by the denominator


-32*5f+25*5f-9=0

Wy multiply elements

-160f+125f-9=0

We add all the numbers together, and all the variables

-35f-9=0

We move all terms containing f to the left, all other terms to the right

-35f=9

f=9/-35

f=-9/35

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