25=kk/5;k=5

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Solution for 25=kk/5;k=5 equation:



25=kk/5k=5
We move all terms to the left:
25-(kk/5k)=0
Domain of the equation: 5k)!=0
k!=0/1
k!=0
k∈R
We add all the numbers together, and all the variables
-(+kk/5k)+25=0
We get rid of parentheses
-kk/5k+25=0
We multiply all the terms by the denominator
-kk+25*5k=0
Wy multiply elements
-kk+125k=0
We add all the numbers together, and all the variables
125k-kk=0

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