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25b(b=10)
We move all terms to the left:
25b(b-(10))=0
We multiply parentheses
25b^2-250b=0
a = 25; b = -250; c = 0;
Δ = b2-4ac
Δ = -2502-4·25·0
Δ = 62500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{62500}=250$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-250)-250}{2*25}=\frac{0}{50} =0 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-250)+250}{2*25}=\frac{500}{50} =10 $
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