25b2+-10b+1=0

Solution for 25b2+-10b+1=0 equation:

25b^2+-10b+1=0

We add all the numbers together, and all the variables

25b^2-10b=0

a = 25; b = -10; c = 0;
Δ = b2-4ac
Δ = -102-4·25·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-10}{2*25}=\frac{0}{50}
=0
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+10}{2*25}=\frac{20}{50}
=2/5
$